[tex]Solution; \\ 8(2f+3)-12=12f-8 \\ \\ 16f+24-12=12f-8 \\ \\ 16f+12=12f-8 \\ \\ 16f-12f=-8-12\ (Transpose) \\ \\ 4f=-20 \\ \\ \frac{4f}{4}=\frac{-20}{4} \\ \\ \boxed{\boxed{f=-5}} \\ \\ Checking; \\ Let\ f\to -5 \\ \\ 8(2f+3)-12=12f-8 \\ \\ 8(2(-5)+3)-12=12(-5)-8 \\ \\ 8(-10+3)-12=-60-8 \\ \\ -80+24-12=-68 \\ \\ -56-12=-68 \\ \\ \boxed{-68=-68}\ \underline{TRUE} \\ \\ Hope\ it\ Helps:) \\ Domini[/tex]
