Sagot :
The width is 31
The length is 21
the missing is the width
52
- 10 --- subtract the feet longer first in the perimeter
----------
42
Then divide 42 ÷ 2 = 21
21+ 10 = 31
the answer is 31
The length is 21
the missing is the width
52
- 10 --- subtract the feet longer first in the perimeter
----------
42
Then divide 42 ÷ 2 = 21
21+ 10 = 31
the answer is 31
let x = the width
let x + 10 = the length
P = 2L + 2W
52 = 2(x+10) + 2x
52 = 2x + 20 + 2x
52 = 4x + 20
52-20=4x
32=4x
1/4(32) = (4x)1/4
8 = x
..therefore, width = x = 8ft
length = x +10 = 8+10 = 18ft
dimension : 18 by 8
let x + 10 = the length
P = 2L + 2W
52 = 2(x+10) + 2x
52 = 2x + 20 + 2x
52 = 4x + 20
52-20=4x
32=4x
1/4(32) = (4x)1/4
8 = x
..therefore, width = x = 8ft
length = x +10 = 8+10 = 18ft
dimension : 18 by 8