Answered

what is the answer of sinΘ(cotΘ+tanΘ)

Sagot :

sinα(cotα+tanα)
=sinα(cosα/sinα + sinα/cosα)
=sinα(cosα/sinα)+sinα(sinα/cosα)
=cosα+sin²α/cosα
=(cos²α+sin²α)/cosα

since cos²α+sin²α=1
therefore,
1/cosα or secα