[tex] Let\ x\ be\ the\ number \\ \\ x\ \cdot40\%=58 \\ \\ x= \frac{58}{40\%} \\ \\ x= \frac{58}{0.40} \\ \\ x=145 \\ \\ Twice\ the\ number; \\ \\ Equation; \\ \\ 2x\to2(145)\to\boxed{\boxed{290}} \\ \\ Conclusion; \\ Thus,290\ is\ the\ answer. \\ \\ Hope\ it\ Helps:) \\ Domini[/tex]
