Asked:
The weight of its son.
Given:
The man weighs 63 ¼ kg. He is 24 ⅔ heavier than its son.
Solution:
[tex]63 \: \frac{1}{4} - 24 \: \frac{2}{3} \\ = 63 \: \frac{3}{12} - 24 \: \frac{8}{12} \\ = 62 \: \frac{15}{12} - 24 \: \frac{8}{12} \\ = 38 \: \frac{7}{12} [/tex]
Answer:
[tex]38 \: \frac{7}{12} \: kg[/tex]
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