Selinaid
Answered

Can you help me and solve this equation? x³-x²-8x+8=0

Sagot :

Bituinid
yep :)

[tex]\\x^3-x^2-8x+8=0 \\ \\x^2(x-1)-8(x-1)=0 \\ \\(x-1)(x^2-8)=0 \\ \\(x-1)(x+\sqrt8)(x-\sqrt8)=0 \\ \\x-1=0 \vee \ x+\sqrt8=0\vee \ x-\sqrt8=0, \ \sqrt8=2\sqrt2 \\ \\Odp. \ x\in\{-2\sqrt2, \ 1, \ 2\sqrt2\}[/tex]