[tex]\\\frac{x+1}{x-1}+\frac{x+5}{x+1}+\frac{2x+1}{x^2-1}=7/*(x+1)(x-1), \ x\in R\backslash\{-1,1\} \\ \\(x+1)^2+(x+5)(x-1)+2x+1=7(x^2-1) \\ \\x^2+2x+1+x^2-x+5x-5+2x+1-7x^2+7=0 \\ \\-5x^2+8x+4=0 \\ \\-5x^2+10x-2x+4=0 \\ \\-5x(x-2)-2(x-2)=0 \\ \\-(5x+2)(x-2)=0 \\ \\5x+2=0 \ \vee x-2=0 \\ \\x=-\frac25 \ \vee \ x=2[/tex]
