LEARNING TASK NO. 3 Find the volume of the following:

Rectangular Prism

| Length | Width | Height | Volume |
8 cm - 4 cm - 12 cm
23 cm - 18 cm - 9 m
35 cm - 20 cm - 16 m

Cube

| Side | Volume |
10 cm
15 cm

Triangular Prism

| Base Area | Height | Volume |
6 cm & 3 cm - 11 cm
8 m & 5 m - 13 m

Pyramid

| Base Area | Height | Volume |
13 cm & 20 cm - 15 m
40 m and 35 m - 25 m

LEARNING TASK NO. 4 Find the volume of the following.

Cylinder

| Radius | Height | Volume |
5 m - 16 m
8 cm - 27 m
3 m 1 - 8 m

Sphere

| Radius | Volume |
3 m
7 cm
12 cm
16 m

Cone

| Radius | Height | Volume |
2 m - 9 m
11 cm 1 - 4 cm

Question

Shiaranevaronaid Shiaranevaronaid

Math

Answered

LEARNING TASK NO. 3 Find the volume of the following:

Rectangular Prism

| Length | Width | Height | Volume |
8 cm - 4 cm - 12 cm
23 cm - 18 cm - 9 m
35 cm - 20 cm - 16 m

Cube

| Side | Volume |
10 cm
15 cm

Triangular Prism

| Base Area | Height | Volume |
6 cm & 3 cm - 11 cm
8 m & 5 m - 13 m

Pyramid

| Base Area | Height | Volume |
13 cm & 20 cm - 15 m
40 m and 35 m - 25 m

LEARNING TASK NO. 4 Find the volume of the following.

Cylinder

| Radius | Height | Volume |
5 m - 16 m
8 cm - 27 m
3 m 1 - 8 m

Sphere

| Radius | Volume |
3 m
7 cm
12 cm
16 m

Cone

| Radius | Height | Volume |
2 m - 9 m
11 cm 1 - 4 cm

Sagot :

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Princesshallaresid Princesshallaresid · Answer 1

Answer:

1. Cylinder

radius = 7 cm

height = 11 cm

Volume = 1693cm³

V=πr

2

h

Solution:

V=π×7

2

×11

V=539π

V=1693cm

3

2. Cone

radius = 4 m

height = 9 m

Volume = 150.79m³

\begin{gathered}\sf{Formula:} \\ \sf{V = \frac{1}{3}\pi {r}^{2} h } \\ \\ \sf{Solution:} \\ \sf{V = \frac{1}{3} \times \pi \times {4}^{2} \times 9 } \\ \sf{V = 48\pi} \\ \sf{V = 150.79 {m}^{3} }\end{gathered}

Formula:

V=

3

1

πr

2

h

Solution:

V=

3

1

×π×4

2

×9

V=48π

V=150.79m

3

4. Rectangular Prism

length = 2 m

width = 6 m

height = 8 m

Volume = 96m³

\begin{gathered}\sf{Formula:} \\ \sf{V = l \times w \times h} \\ \\ \sf{Solution:} \\ \sf{V = 2 \times 6 \times 8 } \\ \sf{V = 96 {m}^{3} }\end{gathered}

Formula:

V=l×w×h

Solution:

V=2×6×8

V=96m

3

5. Pyramid

length = 25 m

width = 13 m

height = 19 m

Volume = 2,058.3m³

\begin{gathered}\sf{Formula:} \\ \sf{V = \frac{l \times w \times }{3} } \\ \\ \sf{Solution:} \\ \sf{V = 2 5\times 13 \times 19 } \\ \sf{V =6,175 \div 3 } \\ \sf{V = 2,058.3 {m}^{3} }\end{gathered}

Formula:

V=

3

l×w×

Solution:

V=25×13×19

V=6,175÷3

V=2,058.3m

3

#carryonlearning

-princesshallares

Wennielencampo18id Wennielencampo18id · Answer 2

Answer:

LEARNING TASK NO. 3

1.) V=6440

Solution

V=whl=23·35·8=6440

-V=1440

Solution

V=whl=18·20·4=1440

-V=1728

Solution

V=whl=9·16·12=1728

2.)Answer:

103=1000

Solution:

103=10×10×10=1000

-Answer:

153=3375

Solution:

153=15×15×15=3375

3.) nasa picture

4.) same

LEARNING TASK NO. 4

1.)Cylinder Calculator

ENTER CYLINDER RADIUS >

ENTER CYLINDER HEIGHT >

5

CALCULATE

16

CLEAR ALL

AREA =157.07963267948966

VOLUME=0

CROSS SECTION=78.53981633974483

-Cylinder Calculator

ENTER CYLINDER RADIUS >

8

ENTER CYLINDER HEIGHT >

27

CALCULATE CLEAR ALL

AREA =1759.291886010284

VOLUME =5428.672105403162

CROSS SECTION =201.06192982974676

-Cylinder Calculator

ENTER CYLINDER RADIUS >

3

ENTER CYLINDER HEIGHT >

8

VOLUME =72 π m3

2.)36 π m3

-457.333333 π cm3

-2304 π cm3

-5461.33333 π m3

3.)12 π m3

-161.333333 π cm3

Step-by-step explanation:

Radius = r

Height = h

Surface Area = 2(π r2) + h(2πr)

Volume = (π r2)h

Cross Section (circle) = π r2