The reversible reaction: 2so₂ + o₂ ⇄ 2so₃ has come to equilibrium in a vessel of specific volume at a given temperature. before the reaction began, the concentrations of the reactants were 0.060 mol/l of so₂ and 0.050 mol/l of o₂. after equilibrium is reached, the concentration of so₃ is 0.040 mol/l. what is the equilibrium concentration of o₂?

[tex]\begin{array}{lccccc} & 2\text{SO}_2 & + & \text{O}_2 & \rightleftharpoons & 2\text{SO}_3 \\ \text{Initial} \: (M): & \: \: \: \: \: \: 0.060 & & \: \: \: 0.050 & & 0 \\ \text{Change} \: (M): & -2(0.020) & & -0.020 & & \: +2(0.020) \\ \hline \text{Equilibrium} \: (M): & \: \: \: \: \: \: 0.020 & & \: \: \: 0.030 & & 0.040 \\ \end{array}[/tex]

Based on the ICE table, the equilibrium concentration of O₂ obtained is

[tex]\boxed{\text{0.030 mol/L}}[/tex]

[tex]\\[/tex]

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