Solve for b
Solve for <A
Solve for <B

pls asap answer

» The given oblique triangle gives two sides and one given angle (SSA). Solve for the third side then the following angles using the law of sines.

Find ∠A:

[tex]\rm \frac{\sin A}{a} = \frac{\sin C}{c} \\[/tex]

[tex]\rm \frac{\sin A}{38} = \frac{\sin 128 \degree}{70} \\[/tex]

[tex]\rm 70(\sin A) \approx 29.94[/tex]

[tex]\rm \frac{70(\sin A)}{70} \approx \frac{29.94}{70} \\ [/tex]

[tex]\rm\sin A \approx \frac{29.94}{70} \\ [/tex]

[tex]\rm\angle A \approx \sin^{ \text - 1} \bigg( \frac{29.94}{70} \bigg) \\ [/tex]

[tex]\rm\angle A \approx 25.32 \degree[/tex]

[tex] \rm [/tex]

Find ∠B:

[tex]\rm \angle A + \angle B +\angle C = 180 \degree [/tex]

[tex]\rm 25.32 \degree + \angle B + 128 \degree \approx 180 \degree [/tex]

[tex]\rm\angle B + 153.32 \degree \approx 180 \degree [/tex]

[tex]\rm\angle B \approx 180 \degree - 153.32 \degree[/tex]

[tex]\rm\angle B \approx 26.68 \degree[/tex]

[tex] \rm [/tex]

Find side c:

[tex]\rm \frac{\sin B}{b} = \frac{\sin C}{c} \\[/tex]

[tex]\rm \frac{\sin 26.68 \degree}{b} \approx \frac{\sin 128 \degree}{70} \\[/tex]

[tex]\rm 31.43 \approx b(\sin 128 \degree)[/tex]

[tex]\rm \frac{31.43}{\sin 128 \degree} \approx \frac{b( \sin 128 \degree)}{ \sin 128 \degree} \\ [/tex]

[tex]\rm 39.89 \approx b[/tex]

[tex]\red{••••••••••••••••••••••••••••••••••••••••••••••••••}[/tex]

#CarryOnLearning