Step 1: Calculate the molar mass of propanol (C₃H₈O).
The molar masses of C, H and O are 12.01 g, 1.008 g and 16.00 g, respectively.
[tex]\begin{aligned} \text{molar mass} & = \text{3(12.01 g) + 8(1.008 g) + 16.00 g} \\ & = \text{60.09 g} \end{aligned}[/tex]
Step 2: Calculate the number of moles of propanol by using dimensional analysis.
[tex]\begin{aligned} \text{moles of} \: \text{C}_3\text{H}_8\text{O} & = \text{42.1 g} \: \text{C}_3\text{H}_8\text{O} \times \frac{\text{1 mol} \: \text{C}_3\text{H}_8\text{O}}{\text{60.09 g} \: \text{C}_3\text{H}_8\text{O}} \\ & = \boxed{\text{0.701 mol}} \end{aligned}[/tex]
Hence, there are 0.701 mol in 42.1 g of ethanol.
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