A solution of methanol is prepared by dissolving 35 ml of methanol in water to give a total of 115 ml solution. what is the percent by volume concentration of methanol?

Sagot :

SOLUTION:

Step 1: List the given values.

[tex]\begin{aligned} & V_{\text{solute}} = \text{35 mL} \\ & V_{\text{solution}} = \text{115 mL} \end{aligned}[/tex]

Step 2: Calculate the percent by volume.

[tex]\begin{aligned} \%(v/v) & = \frac{V_{\text{solute}}}{V_{\text{solution}}} \times 100\% \\ & = \frac{\text{35 mL}}{\text{115 mL}} \times 100\% \\ & = 30.43478\% \\ & \approx \boxed{30.4\%} \end{aligned}[/tex]

Hence, the percent by volume concentration of methanol is 30.4%.

[tex]\\[/tex]

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