Cube of binomial pattern, where a = first term and b = second/last term:
(a + b)³ = (a + b) (a + b) (a + b)
= a³ + 3a²b + 3ab² + b³
Steps in finding the special product of (a + b)³ :
a) Cube the first term, a = a³
b) Three (first term)² (last term) = 3 (a)² (b) = 3a²b
c) Three (first term) (last term)² = 3 (a) (b)² = 3ab²
d) Cube the last term = b³
Combine the results, the special product is:
a³ + 3a²b + 3ab³ + b³
