at a distance 100 m from a building, the angle of elevation of the top of the building is 50
.how tall is the building?

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Math

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at a distance 100 m from a building, the angle of elevation of the top of the building is 50
.how tall is the building?

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Анонимid Анонимid · Answer 1

Анонимid Анонимid

tan θ = opposite / adjacent

Let x be the height of the building, the opposite
tan θ = tan 50° ( angle of elevation)
Distance from the building = 100 m, the adjacent

tan 50° = x / 100
tan 50° (100) = x
x = 1.1918 ( 100)
x = 119.18 m

ANSWER: The building is 119.18 meters tall.

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