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The perimeter of a Rectangle is 64cm, if the length is 4cm more than the width, what is its area?

Sagot :

Area of rectangle= L × W
Perimeter of rectangle = 2(L) × 2(W)

Width:  x
Length: x + 4   (4 cm more than width)
Permimeter: 64 cm

Solve for x using formula of perimeter:
64 = 2 (x) + 2(x + 4)
64 =2x + 2x + 8
64 = 4x + 8
4x = 64 - 8
4x = 56
4x/4 = 56/4
x = 14

Dimension:
Width: x = 14 cm
Length: x + 4 cm = 14 cm + 4 cm = 18 cm
 
Solve for Area:
Area = L × W
Area = (18 cm) (14 cm)
Area = 252 cm²

ANSWER:  The area of rectangle is 252 cm².
Perimeter = 2(l + w)
Area = lw

let x = be the width
x + 4 = be the length

2(x + x + 4) = 64
2(2x + 4) = 64
4x = 64 - 8
[tex] \frac{4x}{4} = \frac{56}{4} [/tex]
x = 14 cm - width
x + 4 = 14 + 4 = 18 cm - length

Area = lw
Area = (14 cm)(18 cm)
Area = 252 cm²