Answer:
22.99
Explanation:
m_{0}(Na)=22.99u*1.661*10^{-24}g/u=3.819*10^{-23}g;m
0
(Na)=22.99u∗1.661∗10
−24
g/u=3.819∗10
−23
g;
This as a single atom, while 1 mole contains of Avogadro number of atoms:
M_{1mol}(Na)=m_{0}(Na)*N_{A}=3.819*10^{-23}g*6.02*10^{23}=22.99g;M
1mol
(Na)=m
0
(Na)∗N
A
=3.819∗10
−23
g∗6.02∗10
23
=22.99g;
Thus, the mole of sodium atoms weights 22.99 grams.
