Answered

If the smallest of three consecutive integers is added to twice the largest the results is seven less than four times the middle integer.find the integer

Sagot :

987 = 9 Highest Integer . 8 middle integer and 7 the smallest integer . The smallest (7) is added to twice the largest(9); is equal to 7 less than 4 times the middle integer(8) . 7 + 2 (9) = 4 (8) - 7 = 25
Three consecutive integers:
First (smallest) integer: x
Second (middle) integer: x + 1
Third (largest) integer: x + 2

Equation: 
smallest integer + 2 (largest integer) = 4(middle integer) - 7

x + 2(x+2) = 4(x +1) - 7
x + 2x + 4 = 4x + 4 - 7
3x + 4 = 4x - 3
4x - 3x = 4 + 3
x = 7

Plug-in 7 to x:
First (smallest) integer: x = 7
Second (middle) integer: x + 1 ⇒ 7 + 1 = 8
Third (largest) integer): x + 2  ⇒ 7 + 2 = 9

ANSWER: The integers in increasing order are 7, 8, 9.

Check:
smallest + 2(largest) = 4(middle) - 7
7 + 2 (9) = 4 (8) - 7
7 + 18 = 32 - 7
25 = 25    (True)