Sagot :
f(x) = 3x + 15
y = 3x + 15
A. To solve for y-intercept, substitute 0 for x:
y = 3x 15
y = 3 (0) + 15
y = 15
y-intercept is at (0,15)
B. To solve for x-intercept, substitute 0 for y:
y = 3x + 15
0 = 3x + 15
3x = -15
3x/3 = -15/3
x = -5
x-intercept is at (-5,0)
y = 3x + 15
A. To solve for y-intercept, substitute 0 for x:
y = 3x 15
y = 3 (0) + 15
y = 15
y-intercept is at (0,15)
B. To solve for x-intercept, substitute 0 for y:
y = 3x + 15
0 = 3x + 15
3x = -15
3x/3 = -15/3
x = -5
x-intercept is at (-5,0)
y = mx + b
f(x) = 3x + 15
y = 3x +15
y-intercept is simply the value of y when x is zero. Also b in the equation so 15.
x-intercept is the value of x when y is zero.
y = 3x + 15
0 = 3x + 15
-3x = 15
-3x/-3 = 15/-3
x = -5
f(x) = 3x + 15
y = 3x +15
y-intercept is simply the value of y when x is zero. Also b in the equation so 15.
x-intercept is the value of x when y is zero.
y = 3x + 15
0 = 3x + 15
-3x = 15
-3x/-3 = 15/-3
x = -5