Sagot :
To find the measure of the interior angle of a polygon, we have the formula...
(n - 2) × 180°
where n is the number of sides. As far as I know, tridecagon have 13 sides.
(13 - 2) × 180°
11 × 180° = 1980
Therefore, the measure of the interior angle of a regular tridecagon is 1980°
(n - 2) × 180°
where n is the number of sides. As far as I know, tridecagon have 13 sides.
(13 - 2) × 180°
11 × 180° = 1980
Therefore, the measure of the interior angle of a regular tridecagon is 1980°
Tridecagon = 13-sided polygon
Measure of an/each interior angle of a tridecagon:
= [tex] \frac{180(n-2)}{n} [/tex] where n = number of sides
= [tex] \frac{180(13-2)}{13} [/tex]
= [tex] \frac{180(11)}{13} [/tex]
= [tex] \frac{1,980}{13} [/tex]
≈ 152.31 degrees.
ANSWER: An interior angle of a regular tridecagon measures approximately 152.31 degrees.
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To find the sum of the measures of the interior angles of tridecagon:
Sum of interior angles = 180° (13-2)
= 180° (11)
= 1,980°
Measure of an/each interior angle of a tridecagon:
= [tex] \frac{180(n-2)}{n} [/tex] where n = number of sides
= [tex] \frac{180(13-2)}{13} [/tex]
= [tex] \frac{180(11)}{13} [/tex]
= [tex] \frac{1,980}{13} [/tex]
≈ 152.31 degrees.
ANSWER: An interior angle of a regular tridecagon measures approximately 152.31 degrees.
-----------------------------------------------------------
To find the sum of the measures of the interior angles of tridecagon:
Sum of interior angles = 180° (13-2)
= 180° (11)
= 1,980°