Solve for b in the equation (x+1) (x+a)=x^2+bx+3..



Sagot :

(x + 1) (x + a) = x² + bx + 3

A)  Solve for a:
    (x + 1) (x + a) = x² + bx + 3
     x² + ax + 1x + 1a = x² + bx + 3
     1a = 3
      a = 3

B) Plug-in 3 to (x + a):
(x + 1) ( x + 3) = x² + 3x + 1x + 3
                        = x² + 4x + 3

ANSWER:  b = 4