give the arithmetic sequence of 5 terms of the first term is 8 and last term is 100.

Sagot :

the arithmetic sequence is 8 31 54 77 100
First, find the common difference using the arithmetic sequence formula:

[tex]a _{n} = a _{1} + (n-1) (d)[/tex]

Where: 
[tex]a _{n} [/tex] = last term  ⇒ 100
[tex]a _{1} [/tex] = first term  ⇒   8
d = common difference (difference between any consecutive terms in the the sequence)

100 = 8 + (5-1)(d)
100 = 8 + 4(d)
100 - 8 = 4d
92 = 4d

4d/4 = 92/4
d = 23

The five terms are:
1st = 8
2nd = 8 + 23 = 31
3rd:  32 + 23 = 54
4th: 54 + 23 = 77
5th: 77 + 23 = 100

The 5 terms in the sequence are:
8, 31, 54, 77, 100