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Six rectangles each with a common base width of 2 have lengths of 1,4,9,16,25 , and 36 . What is the sum of the areas of the six rectangles?

Sagot :

Syannmeid
To find the area of the rectangle is simply the width times the length. The width is already given which is 2 so you just multiply it to each of the given lengths of the rectangle and then add.

(1x2) + (4x2) + (9x2) + (16x2) + (25x2) + (36x2) = 2 + 8 + 18 + 32 + 50 + 72 = 182 square units
Because the width and the length was already given, let's just find their area and add it.

[2(1)] + [2(4)] + [2(9)] + [2(16)] + [2(25)] + [2(36)]
    2   +    8     +   18   +      32   +    50    +      72 = 182

Therefore, the sum of the areas (in other words, the answer) is 182 units²