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What is the equation of the line through the points (3, -1) and (5, -3)?

Sagot :

If you're trying to find the distance, the distance is the square root of (x sub 2 minus x sub one) ^2 plus (y sub 2 minus y sub 1)^2
y- (-1) = [tex] \frac{-3-(-1)}{5-3} (x-3)[/tex]

y + 1 = [tex] \frac{-3+1}{2} (x-3)[/tex]

y = ⁻²/₂ (x-3) - 1

y = -x + 3 - 1

y = -x + 2  Slope-intercept Form

x + y = 2  Standard Form Equation

x + y - 2 = 0 General Form Equation


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