Let's make a balance equation for this
Potassium hydroxide = KOH
hydrogen chloride = HCl
HCl + KOH → KCl + H2O
In this equation, the ratio of the number of mole of HCl to the number of mole of KOH is 1:1.
The molar mass of HCl is 36.46.
The molar mass of KOH is 56.11.
Let's start to solve
[tex]18.25g HCl [ \frac{1 mol HCl}{36.46g HCl}][ \frac{1 mol KOH}{1 mol HCl}][ \frac{56.11g KOH}{1 mol KOH}] = 28.09 g KOH[/tex]
Therefore, there are 28.09 g of Potassium hydroxide needed to neutralize 18.25 g of hydrogen chloride.
