pedro spent 1/2 in the first store then he spent 1/4 of what he had left in the second store.after he spent 60 pesos in the third store ,he had no money left.how much did he have at first?

P240 is the answer
because 60 is your basis and 1/2 and 1/4 are your guide so you need to form 1 whole. 60 is just 1/4. multiply 60 x 4. that's the answer.

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Анонимid Анонимid · Answer 2

Pedro's money: x
Money spent on first store: ¹/₂ (x)
Money spent on second store: ¹/₄ (¹/₂) (x)
Money spent on third store: 60

Equation:

x - [ 1/2(x) + 1/4 (1/2)(x) + 60) ] = 0
x - [ 1/2(x) + 1/8(x) + 60 ] = 0

Change the sign of each term of the subtrahend [1/2(x) + 1/8 (x) + 60]:
x + [-¹/₂ x - ¹/₈ x - 60] = 0
x + (-⁴/₈ x - ¹/₈ x) - 60 = 0
x - ⁵/₈ x = 60

LCD: 8
(8)x - (8) ⁵/₈ x = (8) (60)
8x - 5x = 480
3x = 480
3x/3 = 480/3
x = 160

ANSWER: Pedro has Php160 at first.

To check, subtract the expenses from Php160:

First store: ¹/₂ x = ¹/₂ (160) = 80 pesos
Second store: (¹/₄) (¹/₂) (160) = ¹/₈ (160) = 20 pesos
Third Store: 60 pesos
Expenses: 80 + 20 + 60 = 160

160 - 160 = 0 ( No money left or all money were spent on three stores)