Question:
A committee consisting of 4 males and 3 females is to be formed. In how many ways can the committee be formed if there are 8 females and 6 males available?
Chooses:
A. 840
B.820
C.780
D.760
Explanation:
The general method
(Permutation and Combination)
[tex] = c \frac{4}{6} \times c \frac{3}{8} [/tex]
[tex] = \frac{6 \times 5 \times 4 \times 3}{4 \times 3 \times 2 \times 1} \times \frac{8 \times 7 \times 6}{3 \times 2 \times 1} [/tex]
(Simplify)
[tex] = \frac{30}{2} \times 50[/tex]
[tex] = 15 \times 50 [/tex]
[tex] = 840ways [/tex]
Answer:
A. =840 ways
