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a shop keeper received a container of fresh eggs. he sold 1/3 of eggs in the morning and sold 320 eggs in the afternoon. at the end of the day he found that 1/4 of the eggs were not sold. how many eggs did he received?

Sagot :

So the algebraic expression here is:

let x-be the number of received eggs

1/3x + 320=(1-1/4)x
1/3x + 320 = 3/4x

Transposing 1/3x to the other side:
320=3/4x-1/3x
320=9/12x-4/12x
320=5/12x

Multiply both sides by 12:
3840=5x
Divided them both by 5:
x=768

So the answer is 768 eggs.

hope this help!
Total eggs received: x
Eggs sold in the morning: 1/3(x)
Eggs sold in the afternoon: 320
Eggs not sold: 1/4 (x)

Equation:
x = 1/3(x) + 1/4 (x) + 320

LCD: (3)(4)
Multiply each term by LCD, then simplify:
(3)(4)x = (3)(4) (1/3) x + (3)(4)(1/4)x + 320 (4)(3)
12x = 4x + 3x + 
12x = 7x + 3,840
12x - 7x = 3,840
5x = 3,840
5x/x = 3,840
x = 768

Answer:  The shop keeper received 768 eggs.

Check:
Eggs sold in the morning: 1/3 (768) = 256 eggs
Eggs not sold: 1/4 (768) = 192 eggs
Eggs sold in the afternoon = 320 eggs

Add:
256 + 192 + 320 = 768
768 = 768   √