Given:
Households with a Dog = 2107
Households with a Cat = 807
Households with both dog and cat = 303
Solution: This is not mutually exclusive events, in other words
the probability that either A or B occurs is the sum of their probabilities
decreased by the probability of both occurring.
Probability (Dog or Cat) = Probability (Dog) + Probability
(Cat) – Probability (both dog and cat)
= [tex] \frac{2107}{5200} + \frac{870}{5200} - \frac{303}{5200} [/tex]
= [tex] \frac{2611}{5200} [/tex]
Ans. [tex] \frac{2611}{5200} [/tex]
