Answer:
Hey!
Yes, f is continuous at x = 1.
Step-by-step explanation:
Solution:
We have to check the three conditions for continuity of a function.
a.) If x = 1, then f(1) = 2
b.) [tex] \overset{\text{lim}}{ \underset{x \longrightarrow1}{}} {x}^{2} - 2x + 3 = 1 - 2 + 3 = 2[/tex]
c.)[tex]f(1) = \overset{\text{lim}}{ \underset{x \longrightarrow1}{}} f(x)[/tex]
Therefore, f is continuous at x = 1.
