m∠S = 58°
m∠E = 2x -1
m∠A = 4x - 3
The sum of the interior angles of ΔSEA is 180 degrees.
58 + 2x - 1 + 4x - 3 = 180
6x + 58 - 4 = 180
6x + 54 = 180
6x = 180 - 54
6x = 126
6x/6 = 126/6
x = 21
Substitute 21 for x:
m∠E = 2(21) - 1
m∠E = 42 - 1
m∠E = 41 degrees ⇒ smallest angle
m∠A = 4(21) - 3
m∠A = 84 - 3
m∠A = 81 degrees ⇒ biggest angle
The opposite segment of the smallest angle is the shortest side.
Segment SA is the shortest side.
The opposite segment of the biggest angle is the longest side.
Segment SE is the longest side.
(Click image below for my illustration of the given triangle with the same solution.)
