Give the quadratic functions y=3x²-4x-5
transform them into the form y=a(x-h)2+k


Sagot :

Transforming to Vertex Form: y=a(x-h)² + k

h = [tex] \frac{-b}{2a} [/tex]

k = [tex] \frac{4ac-b^{2} }{4a} [/tex]

Given:
y = 3x² - 4x - 5

a = 3;   b = -4;    c = -5

h = -(-4)
     2(3)

h = 4/6

h = 2/3


k = 4(3) (-5) - (-4)
²
         4(3)

k = -60 - 16
          12

k = -76
      12

k = -19/3


Substitute the values of a, h and k to the vertex for:

y = a(x - h)² + k

y = 3 (x- 2/3)² + (-19/3) 

Vertex Form:  y = 3(x-2/3)² - 19/3