Answered

two water pipes can fill an empty tank in 10 hr. if the larger pipe can fill the tank in 4.5hrs less time than is required by the smaller pipe how long will it take each pipe alone to fill the tank

Sagot :

Rate * Time = Work Pipe Large 1/x*1ohrs =10/x Pipe Small 1/x+4.5*10hrs=10/x+4.5 10/x+10/x+4.5=1 x^2-15.5x-45 x=18 Pl =18 Ps= 18 +4.5=22.5 Pipe Large = 18hrs Pipe Small= 22.5hrs
It takes 22.5 for smaller pipe to fill the tank alone.

It takes 18 hours for larger pipe to fill the tank alone.

(Please attached solution.)
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