3x^2-2x+2=0

find quadratic equation


Sagot :

Use Quadratic Formula:

[tex]x = \frac{-b+or- \sqrt{(b) ^{2}-4ac } }{2a} [/tex]

a = 3;      b =  -2;        c=2

[tex]x = \frac{-(-2)+or- \sqrt{(-2) ^{2}-4(3)(2) } }{2(3)} [/tex]

[tex]x = \frac{2+or- \sqrt{4-24} }{6} [/tex]

[tex]x= \frac{2+or- \sqrt{20} }{6} [/tex]

[tex]x= \frac{2+or- \sqrt{(4)(5)} }{6} [/tex]

[tex]x= \frac{2+or- 2\sqrt{5} }{6} [/tex]

The roots are:
[tex]x = \frac{1}{3} + \frac{1}{3} \sqrt{5} i[/tex]

[tex]x= \frac{1}{3} - \frac{1}{3} \sqrt{5} i[/tex]