I am four digit-number. I am divisible by 3. My first digit is the square root beer of my third digit. Fourth digit is four more than my first digit. And my second digit is the deference between my third and fourth digit. What number am i?

My first digit is the square root beer of my third digit.
2^2=4 or 3^2 =9
Fourth digit is four more than my first digit
9/4=2.25 means this is not
4/1 = 4 this is the first number
1 is the 4th number
2 is the 3rd number
since the last digit is divisible by 3 and the 3rd number is 2 that is between 21, 24, 27
And my second digit is the deference between my third (which is 2) and fourth digit (which is 1).
1+2=3
3-2=1
3-1=2
so the 2nd number is 3

Misscheskaid Misscheskaid · Answer 2

WHAT NUMBER AM I?

Answer:

3297

Step-by-step explanation:

First, analyze the key points in the given:

I am four digit-number
I am divisible by 3
My first digit is the square root beer of my third digit
Fourth digit is four more than my first digit
My second digit is the difference between my third and fourth digit

What number am I?

Since it has 4 digits, look for 4 digit-number that is divisible by 3.

Make sure to fulfill all of the conditions given.

Find a 4-digit number that is divisible by 3 in which:

The first digit is the square root beer of the third digit (3 is the square root of 9);
The fourth digit is four more than the first digit (3 + 4 = 7); and
The second digit is the difference between my third and fourth digit (9 - 7 = 2).

Hence, the answer is 3297.

For more reference of related topic: brainly.in/question/13008672

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