The sum of two numbers is 124. Three times the smaller numbers exceeds the larger number by 12. Find the numbers.

Sagot :

Let x be the smaller number and y be the larger number. Then,
x + y = 124
3x = y + 12

First equation can be transformed as x = 124 - y.

Substituting this to the second equation, we have,
3(124 - y) = y + 12
372 - 3y = y + 12
-3y - y = 12 - 372
-4y = -360
y = 90

Substituting the value of y to either of the two equations, we have,
x + y = 124
x + 90 = 124
x = 124 - 90
x = 34

Therefore, the two numbers are 34 and 90.



- D.E.