3x+2z=5
2y+3z=5
X+3y-z=3


Sagot :

The solution set is:
( x, y, z) = (1, 1, 1)

Solution:
it is on the picture I uploaded, I used Gaussian Elimination Method then I solve.

Check:
3(1) + 2(1) = 5
3 + 2 = 5
5 = 5

2(1) + 3(1) = 5
2 + 3 = 5
5 = 5

1 + 3(1) - 1 = 3
1 + 3 - 1 = 3
4 - 1 = 3
3 = 3

So, definitely, the values of x, y, and z are all 1.


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