The line passes through the origin and has slope of -2/3

Sagot :

Origin (0,0)  m= -2/3

y-y1 = m (x-x1)

[tex]y - 0 = - \frac{2}{3} (x-0)[/tex]

[tex]y = - \frac{2}{3} x[/tex]  

Equation of the line in form y=mx + b:
[tex]y = - \frac{2}{3} x[/tex]

Equation of the line in standard form, ax + by = c:
[tex]y = - \frac{2}{3} x[/tex]
[tex](3)(y) = (- \frac{2}{3} x) (3)[/tex]
[tex]3y = -2x[/tex]
2x + 3y = 0