If y varies inversely as x and y=1/3 when x=8, find y when x=-4

Sagot :

y = k/x

y = 1/3 x = 8  k = ?

[tex] \frac{1}{3} = \frac{k}{8} [/tex]
[tex]k = ( \frac{1}{3} )(8)[/tex]
[tex]k = \frac{8}{3} [/tex]

y = ?    x = -4    k = 8/3

[tex]y = \frac{ \frac{8}{3} }{-4} [/tex]
[tex]y = ( \frac{8}{3}) (- \frac{1}{4} )[/tex]
[tex]y = - \frac{8}{12} [/tex]

[tex]y = - \frac{2}{3} [/tex]