If a rectangle has a length that is 3cm less than four times its width and its perimeter is 19cm,what are the dimensions?

Sagot :

Let width be x
Length be 4x - 3
Perimeter = 19 cm

Perimeter = 2 (w) + 2 (L)
19 = 2 (x) + 2 ( 4x-3)
19 = 2x + 8x - 6
19 = 10 x - 6
19 + 6 = 10 x

10x/10 = 25/10

x = 2.5

Substitute 2.5 for x; The dimensions are:

Width (x) = 2.5 cm
Length (4x-3) = 4(2.5)-3 = 10 -3 = 7 cm

To check:

2 (2.5 cm) + 2 (7 cm) = 19 cm
5 cm + 14 cm = 19 cm
19 cm = 19 cm
i THINK THE ANSWER IS X=2.5