a certain two digit number is equal to 9 times the sum of the digits. if 63 were subtracted from the number , the digits would be revised.find the number. Hint: if x is the tens' digit and y the units' digit, the value of the number is 10x+y

Sagot :

10x + y = 9 (x+ y)
(10 x + y) - 63 = 10y + x

10x + y = 9x + 9y
x = 8y

10x + y = 10y + x + 63
9x = 9y + 63
9 (8y) = 9y + 63
72y = 9y + 63
63y = 63
y = 1
x = 8 (1)
x = 8 

The number is 81.