Answered

find the least number which when increased by 5 is divisible by 12,14,18 and 21.

Sagot :

Mlcparra16id
First we look for the LCM of 12, 14, 18, and 21
12 = 2² * 3
14 = 2 * 7
18 = 2 * 3²
21 = 3 * 7

LCM = 2² * 3² * 7 = 252

Therefore the least number is 252 - 5 = 247.
AwesomeHelperid
We just have to find the LCM of 12, 14, 18, and 21 and then subtract 5 from it.
The LCM of 12, 14, 18, and 21 is 252.
252 - 5 is 247

So the number is going to be 247
247 + 5 = 252
252 / 21 = 12
252 / 18 = 14
252 / 14 = 18
252 / 12 = 21

So therefore, the least number when increased by 5 that is divisible by 12, 14, 18, and 21 is 247.