Sagot :
First number: x
Second number: x + 4 (four more than the first number)
Third number: (x+4) + 4 or x+8 (four more than the second number)
Sum of the numbers = 117
(x) + (x+4) + (x+8) = 117
3x + 12 = 117
3x + 12 - 12 = 117 - 12
3x = 105
3x/3 = 105/3
x = 35
The numbers are:
First: x = 35
Second number: x + 4 = 35 + 4 = 39
Third number: (x + 4) + 4 = 35 + 8 = 43
To check:
35 + 39 + 43 = 117
Second number: x + 4 (four more than the first number)
Third number: (x+4) + 4 or x+8 (four more than the second number)
Sum of the numbers = 117
(x) + (x+4) + (x+8) = 117
3x + 12 = 117
3x + 12 - 12 = 117 - 12
3x = 105
3x/3 = 105/3
x = 35
The numbers are:
First: x = 35
Second number: x + 4 = 35 + 4 = 39
Third number: (x + 4) + 4 = 35 + 8 = 43
To check:
35 + 39 + 43 = 117