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if 3x+4 varies directly as y - 2 and x=4 when y=4, find x when y=10

Sagot :

Variation Equation:
3x+4 = k (y-2)

x = 4; y=4

3(4) + 4 = k (4-2)
12 + 4 = k (2)
16 = k(2)
16/2 = 2k/2
k = 8

x = ? ; y = 10
3x + 4 = k(y-2)

3x + 4 = 8(10-2)
3x + 4 = 8(8)
3x + 4 = 64
3x + 4 -4 = 64 - 4
3x = 60
3x/3 = 60/3
x = 20, Final Answer

To check when y=10, and x = 20
3(20) + 4 = 8 (10-2)
60 + 4 = 8 (8)
64 = 64

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