Beadeveyra0325id
Answered

what is (k^3-4k^2-30k-18)/(k+3)

Sagot :

Lightningflashid
k^2-7k-9+9/k+3 is the answer
Solving by method long algorithm:
 The quotient is:

[tex]k ^{2} -7k-9 + \frac{9}{k+3} [/tex]

where the remainder is:
[tex] \frac{9}{k+3} [/tex]