Finding the linear equation through graphing
(1,-1) ,(3,5)


Sagot :

Given two points (1, -1) (3,5)
x1 = 1   y1 = -1
x2 = 3   y2 = 5

y - y1 = y2 - y1 (x-x1)
            x2 - x1

Substitute the values:
y - -1 = 5 - -1 (x - 1)
            3 - 1

y+1 = 5+1 (x-1)
           2

y = 6/2(x-1) -1
y = 3(x-1)-1
y = 3x -3 - 1
y = 3x - 4  , slope-intercept form

Equation in Standard for, ax + by = c
3x - y = 4

Equation in general form, ax + by +c = 0
3x - y - 4 = 0