find three consecutive odd numbers whose sum is 69

Sagot :

(x-2) + x + (x+2) = 69
3x - 69 -> x - 23

the numbers are 21, 23 and 25.
Let the first odd number be x
second odd number be x+2
third odd number be x+4
the sum of the three consecutive odd integers = 69

Equation:

(x) + (x+2) + (x+4) = 69
3x + 6 = 69

3x = 69 - 6
3x = 63

3x/3 = 63/3
x = 21

The three consecutive odd integers are:
x = 21
x+2 = 23
x + 4 = 25

To check:
21 + 23 + 25 = 69
69 = 69