Sagot :
Lat n be the largest number in the given counting numbers:
n(n+1) = sum of the counting (consecutive) numbers
2
10 000 (10 000 + 1) = 10 000 (10 001) = 100 010 000 = 50,005,000
2 2 2
The Final answer is 50 005 00
n(n+1) = sum of the counting (consecutive) numbers
2
10 000 (10 000 + 1) = 10 000 (10 001) = 100 010 000 = 50,005,000
2 2 2
The Final answer is 50 005 00
Solution: The sum of consecutive integers from 1 to n
sum= n(n+1) ⇒sum=10000x(10001)= 50 005 000
2 2
sum= n(n+1) ⇒sum=10000x(10001)= 50 005 000
2 2