find the 9th term of the arithmetic sequence with a1 = 10 and d = -½

Sagot :

Answer:

In this sequence, where d = -1/2 = -0.5 and the first term is 10

   10, 9.5, 9, 8.5, 8, 7.5, 7, 6.5, 6, ...

The 9th term is 6.

Step-by-step explanation:

Arithmetic sequence formula is

an = a1 + (n-1)(d)

where;

an = is the term

a1 = the first term

n = the  order of the term in the given

d = common difference (difference between the consecutive sequence must be the same

Given:

a9 = ?

a1 = 10

n = 9 (9th term)

d =  -1/2

a9 = 10 + (9-1) (-1/2) Subtract 9 - 1 first

a9 = 10 + (8) (-1/2) Multiply 8 * (-1/2)

a9 = 10 + (-4) Simplify 10 + (-4)

a9 = 6

The 9th term is 6.

If the common difference is negative (-), the sequence is in decreasing order:

In this sequence, -1/2 = -0.5

   10, 9.5, 9, 8.5, 8, 7.5, 7, 6.5, 6, ...

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