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if (x-4) varies inversely as (y+3) and x=8 when y-2, find x when y=-1

Sagot :

(x-4) = k
        (y+3)

x=8; y= -2
(8-4) = k      
       (-2 + 3)

4 = k     
       1

k = (4)(1)
k = 4

when y = -1; x = ?
x-4 = 4   
       -1+ 3

x-4 = 4/2
X-4 = 2
x = 2 + 4
x = 6

Final answer, x = 6

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