equation problems with solutions


Sagot :

Find four consecutive even integers whose sum is 524.

Let first even integer: x
       second even integer: x + 2
       third consecutive even integer: X + 4
       fourth consecutive even integer: x + 6
       Sum= 524

Add:

(x) + (x+2) + (x+4) + (x+6) = 524
4x + 12 = 524
4x = 524 - 12
4x = 512

4x  =  512
 4         4
x =  128

The four consecutive integers are
first:  x = 128
second : x + 2 = 128 + 2 = 130
third:  x + 4 = 128 + 4 = 132
fourth: 128 + 6 = 134

FINAL ANSWER:  The four consecutive even integers are 128, 130, 132 and 134
Cody is twice as old as Evan. Three years ago, the sum of their ages was 27. Find the age of each boy now.                
 
                                                                        
Representation: 
Let x = Evan's age     
                          2x = Cody's age         
                                                 
                                             Three years ago                      Now        
                   Cody                          2x - 3                                2x         
                   Evan                          x - 3                                   x          
                                      
Equation: (2x - 3) + (x - 3) = 27

Solution: (2x - 3) + (x - 3) = 27
               2x - 3 + x - 3 = 27
               3x - 6 = 27
               3x = 33
              -----   -----  ⇒ x = 11; 2x = 22
                3      3 

Answer: Cody is 22 while Evan is 11.

Check: (2x - 3) + (x - 3) = 27
            [2(11) - 3] + (11 - 3) = 27
            (22 - 3) + 8 = 27
            19 + 8 = 27
            27 = 27

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